2x^2+3x-4+8-3x+(-5x^2)+2=

Solution for 2x^2+3x-4+8-3x+(-5x^2)+2= equation:

Simplifying
2x2 + 3x + -4 + 8 + -3x + (-5x2) + 2 = 0

Reorder the terms:
-4 + 8 + 2 + 3x + -3x + 2x2 + (-5x2) = 0

Combine like terms: -4 + 8 = 4
4 + 2 + 3x + -3x + 2x2 + (-5x2) = 0

Combine like terms: 4 + 2 = 6
6 + 3x + -3x + 2x2 + (-5x2) = 0

Combine like terms: 3x + -3x = 0
6 + 0 + 2x2 + (-5x2) = 0
6 + 2x2 + (-5x2) = 0

Combine like terms: 2x2 + (-5x2) = -3x2
6 + -3x2 = 0

Solving
6 + -3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -3x2 = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -3x2 = 0 + -6
-3x2 = 0 + -6

Combine like terms: 0 + -6 = -6
-3x2 = -6

Divide each side by '-3'.
x2 = 2

Simplifying
x2 = 2

Take the square root of each side:
x = {-1.414213562, 1.414213562}